Re: How to check out a project based on commit time rather than rev?

On May 18, 2018, at 17:01, Bo Berglund wrote:

> So now I know what has happened and I found the revision numbers for
> two revisions that were committed erroneously last December when I was
> preparing for the CVS -> SVN migration.
> These revisions are 4309 and 4310
>
> Now my problem is in finding the correct svn command to restore the
> trunk files to the state they were in prior to commit r4309.
>
> I have googled a lot tonight and read the svnbook too but I am none
> the wiser (not so that I dare run a command and risk screwing up the
> repository).
> I have some candidates within the top dir of a WC of the
> project/trunk:
>
> svn merge -c 4308:HEAD .
>
> svn merge -r 4308:HEAD .
>
> svn merge -r 4309:HEAD .
>
> svn merge -c COMMITTED:PREV .
>
> Questions:
> ----------
> 1) Use -c or -r?
>
> 2) Which order of revision numbers?
>
> 3) What to do to restore to two revisions back?

When merging:

"-c 500" is a shorthand synonym for "-r 499:500".

"-r 499:500" means "the set of steps to turn r499 into r500".

You'll use this if you want to repeat what you did in a revision, for example to make the same change on another branch.

If instead you want to undo a change you already committed, then you'll want to merge in the reverse order: "-r 500:499" to turn 500 back into 499, or using the shorthand: "-c -500".

If you want to do two revisions at once, just extend the range, e.g. "-r 498:500" is the steps to turn r498 into r500.

So if you want to undo what you did in revisions 4309 and 4310, you would merge "-r 4310:4308".

http://svnbook.red-bean.com/en/1.7/svn.branchmerge.basicmerging.html#svn.branchmerge.basicmerging.undo
Received on 2018-05-19 02:06:10 CEST