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Re: Can import also convert the source to a working copy

From: Branko ─îibej <brane_at_apache.org>
Date: Thu, 15 Mar 2018 12:04:20 +0100

On 15.03.2018 11:48, Bo Berglund wrote:
> I have used this sequence for handling new projects with svn:
> - Start a new project in whatever IDE is used
> - Work a bit on initial code so the framework is OK
> - Exit the IDE
> - Command prompt in the parent of the project dir
> - svn import <project dir name> <svn URL> --depth files -m "message"
> - rename <project dir> <something else>
> - svn co <svn URL> <project dir>
> - move <something else>\<all subdirs> <project dir>\
> - delete <something else>
> - start dev IDE again and hopefully find that it loads properly
> I want to avoid having to do all the steps following the svn import
> command so I can just continue working where I was when I wanted to
> put the project under version control.
> Specifically there may be ignored files in the project dir that are
> needed by the dev IDE but should not be versioned and I would like
> these to be intact yet not part of the versioning. I have svn ignores
> in my config file so they won't be part of the import and therefore
> they will not appear after the following checkout...
> Is there some flag or such that can help out during the import or in a
> following checkout so that the extra directory >something else> does
> not need to be used?
> Or can I just move the .svn dir from the working copy to the original
> project and then it will be converted in place?

svn checkout --force

-- Brane
Received on 2018-03-15 12:04:25 CET

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