> -----Original Message-----
> From: Giulio Troccoli [mailto:Giulio.Troccoli_at_uk.linedata.com]
> Sent: Friday, May 02, 2008 10:10 AM
> To: users_at_subversion.tigris.org
> Subject: Efficient way to get the previous revision number
>
> Given a revision number I need to find out the revision of the
previous
> commit in a particular directory. For example, with revision 100 I
> committed some change to src/dir1. Then, with revision 101 to 104 I
> committed changes to src/dir2. Now, with revision 105 I committed
> changes again in src/dir1. So given revision 103, and the directory
> src/dir1 of course, I need to find the previous revision, i.e. 100.
>
> What I am doing at the moment is something like
>
> svn --quiet log [dir1 URL] 103:1 | head -2 | tail -1 | cut -d" " -f1 |
> cut -dr -f2
>
> I thought about using the --limit option but that would give me 105
(in
> the example above) which is not what I'm after.
>
> My script works just fine, but I think that getting the log from
> revision 1 is a bit too much, since I just need the last one.
>
> Does anybody think of a better, more efficient, way to achieve this?
>
> I'm using SVN 1.4.4 and ksh for the script.
>
--limit does work. (I'm using 1.4.5.)
svn log -q -r 103:1 --limit 1 URL | ...
Using a peg revision should also work:
svn log -q --limit 1 URL_at_103 | ...
> I thought about using the --limit option but that would give me 105
(in
> the example above) which is not what I'm after.
It should give you 100, not 105. Svn log goes down, not up.
*****
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Received on 2008-05-02 19:02:04 CEST