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RE: svn grep -r2:5 "a_word" filename1 filename2 folder3

From: Reedick, Andrew <Andrew.Reedick_at_BellSouth.com>
Date: 2006-09-20 18:33:50 CEST

> -----Original Message-----
> From: Hanley, James [mailto:jhanley@redcom.com]
> Sent: Wednesday, September 20, 2006 11:58 AM
> To: users@subversion.tigris.org
> Subject: svn grep -r2:5 "a_word" filename1 filename2 folder3
>
> A while back, there was a request for the ability to grep through the
> source tree of subversion.
>
> http://subversion.tigris.org/servlets/ReadMsg?listName=users&m
sgNo=6804
>
> The response mentions using blame, but specifically I would like to
> search for (for example) some structure that existed at one point that
> was removed and what version it was removed from.
>
> The problem is that using svn blame seems to only produce the
> up-to-date
> snapshot of a given version. What I want is the last version
> the string
> was seen in.
>
> If there is a way of doing this without regressing through
> every version
> of a file, I would like to know, and if there is currently no way of
> doing this, I believe it would be a valuable feature to Subversion.

./rev_grep.sh URL[@PEG_REV] regex

The PEG_REV only works in svn 1.4.0 or higher. ('svn log' supports peg
revs in 1.4.0)

rev_grep.sh
=====================
#!/bin/ksh

URL=$1
REGEX=$2

LAST_REV="n/a"

svn log -q $URL | perl -ne 'print "$1\n" if /^r(\d+)/' |
while read r
do
    ##svn cat -r $r $URL | grep "$REGEX" > /dev/null
    BUFFER=`svn cat -r $r $URL | grep "$REGEX"`
    RET=$?
    if [ $RET -eq 0 ]
    then
        echo "Match in revision: $r. Removed in $LAST_REV."
        echo $BUFFER

        exit 0

    elif [ $RET -ne 1 ]
    then
        ## grep hit an error
        exit 2
    fi

    LAST_REV=$r
done
exit 1

*****

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Received on Wed Sep 20 18:38:07 2006

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