Limit on number of consecutive ls's?

Hi,

Trying to do some basic timing measurements, I wrote the following Python
code:

---------------------------------------------------------------------------
...
def main(pool, url):
    revision = svn.core.svn_opt_revision_t()
    revision.kind = svn.core.svn_opt_revision_head
    config = svn.core.svn_config_get_config( None, pool )
    ctx = svn.client.svn_client_create_context(pool)
    ctx.auth_baton = svn.core.svn_auth_open([], pool)
    ctx.config = config
    for i in range(10000):
        print i
        files = svn.client.svn_client_ls( url, revision, 0, ctx, pool )
...
---------------------------------------------------------------------------

Running this program always gives the following output:

---------------------------------------------------------------------------
...
1015
1016
1017
1018
Traceback (most recent call last):
  File "./svnls", line 34, in ?
    svn.core.run_app(main, sys.argv[1])
  File "/usr/lib/python2.3/site-packages/svn/core.py", line 33, in run_app
    return apply(func, (pool,) + args, kw)
  File "./svnls", line 16, in main
    files = svn.client.svn_client_ls( url, revision, 0, ctx, pool )
libsvn._core.SubversionException: ('Unable to open an ra_local session to
URL', 180001)
---------------------------------------------------------------------------

Why does it fail at the 1020th call? Is it an anti-hacker feature, is my code
wrong, or is it *gasp* a bug? Where does that magic 1020 number come from?

Thanks!

PS. Complete test program is attached.

-- 
Simon Perreault <nomis80_at_nomis80.org> -- http://nomis80.org

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