skip_uri_scheme question

In this function:

static const char *
skip_uri_scheme(const char *path)
{
   apr_size_t j;

   for (j = 0; path[j]; ++j)
     if (path[j] == ':' || path[j] == '/')
        break;

   if (j > 0 && path[j] == ':' && path[j+1] == '/' && path[j+2] == '/')
     return path + j + 3;

Why do we check for a ':' and a '/' in the for loop to break out early but only
return success if that first character is a ':' in the second if?

Thanks,
Blair

-- 
Blair Zajac, Ph.D.
<blair@orcaware.com>
Subversion training, consulting and support
http://www.orcaware.com/svn/
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