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Re: [PATCH] mail address handling in mailer.py

From: Branko ─îibej <brane_at_xbc.nu>
Date: 2006-06-08 16:56:56 CEST

Mathias Weinert wrote:
> Branko Cibej wrote:
>
>> Mathias Weinert wrote:
>>
>>> Adding a new option 'to_addrs' is okay for me. So the following questions
>>> have to be answered:
>>>
>>> o Do we use to_addr only if to_addrs isn't set or do we combine them?
>>> -> I would say use only one of them.
>>>
>>> o Which character will be used for splitting?
>>> -> Although several (most) mail clients use ',' I could also accept to
>>> use the semicolon ';'. So is it ',' or ';'?
>>>
>>> o Do we want to use your code example to make the splitting process more
>>> smart?
>>> -> In order to not make it too complicated I would say 'No' (although
>>> I appreciate your code example).
>>>
>>> What do you think?
>>>
>>>
>> I think it's a waste of time to write this kind of parser in Python. :)
>>
>> Teach mailer.py to expect a Python list in the to_addr option it the
>> character in the option value is a bracket. So, if you write:
>>
>> to_addr = [ 'list',
>> 'of',
>> 'mail',
>> 'addresses' ]
>>
>> you can simply evaluate the option's value and get a Python list object.\
>> On the con side, the list elements would have to be valid Python
>> strings, using Python's quoting rules.
>>
>
> At first thought, yes, great idea. No changes of config file needed
> (except a comment about the new feature), no deprecation and my goal
> achieved.
>
> But then I tried to implement the "you can simply evaluate
> the option's value and get a Python list object." idea...
> After doing some internet research I found out that there doesn't seem
> to be any simple way to do this.
>
> So unless you are able to tell me how to simply do the string to list
> conversion we have to find another solution.
>
So much for "internet research," then.

$ python
Python 2.4.2 (#67, Sep 28 2005, 12:41:11) [MSC v.1310 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> p = eval("['this', 'is', 'a', 'list', 'of', 'strings']")
>>> print p
['this', 'is', 'a', 'list', 'of', 'strings']
>>> print ' '.join(p)
this is a list of strings
>>> ^Z

I fail to see how it could be simpler.

-- Brane

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Received on Thu Jun 8 17:01:03 2006

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