Ben Collins-Sussman <sussman@collab.net> writes:
> Karl Fogel <kfogel@newton.ch.collab.net> writes:
>
> > But, we'll have to transmit the dirty bit to the server somehow. That
> > is, if you tell the server you have directory D at revision 9, and
> > then tell it you have the following children of D also at revision 9,
> > the server won't assume that any unmentioned children are deleted --
> > it will assume they're also at revision 9! :-) So state reports will
> > need to incorporate the dirty bit, probably not too difficult (?)...
>
> Yeah, very easy to do. Just add a new callback to the state-report
> language that means "this dir is dirty". The server interprets the
> command by removing all children of the directory. Then the client
> uses existing report language commands to rebuild all the children
> that it has.
/me needs make sure he understands what we're talking about here.
You're advocating this:
copy into the txn revision X of dir
if (dir is dirty):
remove all of X's children
foreach child of X the working copy has:
add back the child to X
versus the old 'deleted flag' way:
copy in revision X of dir
foreach child of X the working doesn't have:
remove child
Do I appear to understand both methods properly?
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Received on Mon Mar 18 22:07:02 2002